<!DOCTYPE html>
<html lang="en">

<head>
    <meta charset="UTF-8">
    <meta http-equiv="X-UA-Compatible" content="IE=edge">
    <meta name="viewport" content="width=device-width, initial-scale=1.0">
    <link href="https://cdn.jsdelivr.net/npm/bootstrap@5.3.0-alpha1/dist/css/bootstrap.min.css" rel="stylesheet"
        integrity="sha384-GLhlTQ8iRABdZLl6O3oVMWSktQOp6b7In1Zl3/Jr59b6EGGoI1aFkw7cmDA6j6gD" crossorigin="anonymous">
    <link rel="stylesheet" href="https://cdnjs.cloudflare.com/ajax/libs/font-awesome/6.3.0/css/all.min.css"
        integrity="sha512-SzlrxWUlpfuzQ+pcUCosxcglQRNAq/DZjVsC0lE40xsADsfeQoEypE+enwcOiGjk/bSuGGKHEyjSoQ1zVisanQ=="
        crossorigin="anonymous" referrerpolicy="no-referrer" />
</head>
</html>
#! /usr/bin/python2.7

# Factorize numbers.
# The algorithm is not efficient, but easy to understand.
# If there are large factors, it will take forever to find them,
# because we try all odd numbers between 3 and sqrt(n)...

import sys
from math import sqrt

def fact(n):
    if n < 1:
        raise ValueError('fact() argument should be >= 1')
    if n == 1:
        return []  # special case
    res = []
    # Treat even factors special, so we can use i += 2 later
    while n % 2 == 0:
        res.append(2)
        n //= 2
    # Try odd numbers up to sqrt(n)
    limit = sqrt(n+1)
    i = 3
    while i <= limit:
        if n % i == 0:
            res.append(i)
            n //= i
            limit = sqrt(n+1)
        else:
            i += 2
    if n != 1:
        res.append(n)
    return res

def main():
    if len(sys.argv) > 1:
        source = sys.argv[1:]
    else:
        source = iter(raw_input, '')
    for arg in source:
        try:
            n = int(arg)
        except ValueError:
            print arg, 'is not an integer'
        else:
            print n, fact(n)

if __name__ == "__main__":
    main()
